Determine terminal velocity ($v_t$) when $F_{net} = 0$.
Compare linear drag ($F_D \propto v$) vs quadratic drag ($F_D \propto v^2$).
Analyze exponential velocity-time curves derived via differential equations.
Key Equations
Linear Drag Model:
\( m\frac{dv}{dt} = mg - bv \)
\( v_t = \frac{mg}{b} \)
Quadratic Drag Model:
\( m\frac{dv}{dt} = mg - cv^2 \)
\( v_t = \sqrt{\frac{mg}{c}} \)
Why It Matters
In AP Physics C, drag is the primary reason why Newton's Laws must be integrated. The opposing force scales dynamically with the object's velocity until $F_{drag}$ perfectly cancels $F_{gravity}$.
Tags
Physics CAir ResistanceDrag ForceDifferential Eqs
3D Drop Visualization
Time ($t$)0.0 s
Current Vel ($v$)0.0 m/s
Accel ($a$)9.8 m/s²
Velocity vs Time ($v-t$ Graph)
Drag Model
Mass $m$ 2.0 kg
Drag Coeff $b$ or $c$ 0.50
Live Analytics
Terminal $v_t$: 39.2 m/s
Gravity $F_g$: 19.6 N
Drag $F_D$: 0.0 N
Quick Quiz
If mass is doubled in a linear drag model ($F_D = -bv$), what happens to $v_t$?